Consecutive Zeros Mobius
Public  04/08/16  8xp  Math  14.9% 
It can easily be seen that there cannot be more than 3 consecutive integers such as $ \mu(n_i) = \pm 1,\quad\mu(n) $ being the Möbius function
However, we can find arbitrary long sequences of consecutive integers with a Möbius value of 0.
Find 9 consecutive integers $ n+1,n+2, ..., n+9 \textrm{ such as }\mu(n+i) = 0$
(Each of them is divisible by a distinct prime square, the primes are the smallest possible).
Answer format: n
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