Segments
Public  09/23/17  6xp  Programming  43.5% 
Let fib(n) be n_{th} Fibonacci number. fib(1)=1, fib(2)=1 and fib(n) = fib(n1) + fib(n2) for n>2. Let f(n)=1+(fib(n)%5) Let v_{N} be the vector of f(i) values for i=1 to N. For example v_{3}=[2, 2, 3] Let T_{N} be the sum of the elements of V_{N}. For example T_{3}=7 Consider an ABC triangle and a D point that bisects BC side: BD=CD Draw the AD segment and assume N1 points on it that further creates N segments such that the lengths of these subsegments are proportional to the elements of v_{N} starting from A to D. s_{i}=v_{N}[i]/T_{N}*AD for i=1 to N Now draw the line segments from C to AB that cross these N1 points on AD segment. So now we have N subsegments on AB side as well. Let the lengths of these subsegments on the AB side be given as t_{i} for i=1 to N starting from A to B. Find the sum of ratios AB/t_{i} for i=1 to N where N = 1919. Answer format: p/q (reduced fraction) You are given that the answer = 251/21 for N = 3.
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